>>748539Hey I'm a little bit late to the party, but just for future reference, whenever you want to find the area between two functions, say f(x) and g(x), on some interval where one of the functions is always "on top" of the other one, you can easily do so by taking the integral of f(x) (the top one) and subtract the integral of g(x) (the bottom one) from it. In this case, you have y1 = lnx and the bottom function being y2 = a (constant function) All you have to do is find int(y1-y2) from e3 to e4. In other words, int(lnx-a) from e3 to e4. Although the method you explained was correct, the way you applied it was wrong. You integrated lnx, which gives you as the other guy said the area of the triangle and the rectangle beneath it. to actually "bring down" the rectangle, you have to subtract a from it. Now this case is fairly easy, but what happens if the bottom of your "triangle" wasn't a flat line but some other function? You would proceed as I said above. That method works in any case, while yours only works when the bottom function is constant.